mysql常见面试题
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三个表关联查询
-- 查询选修了所有课程的学生姓名
SELECT sname FROM student WHERENOT EXISTS (SELECT cname FROM course WHERENOT EXISTS (SELECT id FROM sc WHERE student.`sid`=sid AND course.`cid`=cid))
对查询结果的操作 1=‘智障’，2=‘傻逼’
SELECT sname,(SELECT CASE WHEN statu = '1' THEN '傻逼' WHEN statu = '2' THEN '智障' ELSE '其他' END) AS statuFROM student WHERE statu=1
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